Puzzles offer an excellent opportunity to engage your intellect and refine your analytical abilities.
Here is an intriguing age question that often sparks curious debate:
When I was 2 years old, my sister was twice my age. Now that I’m 40, how old is my sister?
Let’s meticulously analyze the components of this conundrum.
Deciphering the Initial Relationship
The core premise:
When your age was 2 years, your sister’s age was double yours. This establishes her age as 4 years at that specific moment.
The crucial insight is to determine the gap in ages between the two individuals, calculated as 4−2=2 years.
Calculating the Present Age
The fundamental principle:
The variance in age between siblings remains perpetually consistent throughout their lives.
Applying this constant difference:
Because your sister is 2 years senior to you, if your current age is 40 years, you must append those 2 years to your present age.
This calculation confirms that your sister’s age currently stands at 42 years.
The Underlying Mathematical Principle
The effectiveness of this riddle lies in its foundation as a straightforward mathematical exercise dependent on grasping the concept of age differences. By correctly identifying and tracking the constant disparity in ages, one can effortlessly compute a person’s age, irrespective of the elapsed time.
Therefore, the next time someone poses the query, “When I was 2, my sister was twice my age. Now I’m 40, how old is she?”—you will possess the precise knowledge that the solution is 42!
Sustaining Mental Acuity
Engaging with brainteasers such as this one is beneficial for maintaining a high level of mental sharpness.
Consider presenting this riddle to your acquaintances and family members to observe how rapidly they can arrive at the correct solution!
